What is the furthest distance on this map that I can send...
Posts: 4291
  • Posted On: Jun 2 2004 10:53pm
...Reinforcments in two posts?
linky linky

I'm trying to figure out the rough distance around each planet that battle reinforcments could arrive in two posts. Larger waits are possible, but short ones are prefferable as I'm trying to figure out good region boundaries for the coalition, so I'll know just how many fleets I'll have to break up our manifest into and how big each should be for the number of planets per region.

Thanks.


[Kas Edit: image is too large to display inline.]
Posts: 4291
  • Posted On: Jun 2 2004 10:57pm
P.S. After posts, I would also like to know what distance I might be able to reach in two HOURS. You know, for planetary shields.
Posts: 4291
  • Posted On: Jun 2 2004 11:07pm
I was thinking the longest distance for two hours might allow someone to travel the distance between Honoghr and Mon Calamari, or Tynna and Ando
Posts: 5387
  • Posted On: Jun 3 2004 12:38am
I was thinking the longest distance for two hours might allow someone to travel the distance between Honoghr and Mon Calamari, or Tynna and Ando


Oh hell no. Kas is going to eat you for breakfast.
Posts: 1913
  • Posted On: Jun 3 2004 1:17am
If its hypserspace, the actual distance doesnt matter.... DUH!

All jumps are the same, the only differance is in non-jumpyness, for dolash's sake!

(nyahaha)
Posts: 2915
  • Posted On: Jun 3 2004 1:28am
it takes two weeks to travel from one side of the galaxy to the other. Use this as a basis.

Technical commentaries has a listing of examples if you need some....
Posts: 4291
  • Posted On: Jun 3 2004 1:49am
Well... Bollox.

That makes things really complicated. I set up the regions, and the longest distance between two planets was Mon Calamari and Honoghr. How long would it take to get from one to the other?
Posts: 7745
  • Posted On: Jun 3 2004 1:58am
Here's a quote I had on file from one of the Mon Cal OOC threads.

Remember that I always go by IC time. For the purpose of this discussion we'll assume that these ships were ready to jump the instant the call was received, no preparations necessary.

Assuming this galaxy is the same diameter as our galaxy, 100,000 light years (this is pretty small, I've heard that the space the Empire alone covered was 120,000ly in diameter, and they by no means had conquered all of the galaxy), and the distance from Honoghr is an 8th of the galaxy (rough measurement I performed with my thumb and forefinger). We're talking about a very low number of 12,500 light years.

Here's a quote from Dark Force Rising:<!--EZCODE QUOTE START--><blockquote><strong><em>Quote:</em></strong><hr> "From the labored sound of the engines, [Mara Jade] could guess they were pushing uncomfortably far past a Victory Star Destroyer's normal flank speed of Point Four Five. Possibly even as high as Point Five, which would mean they were covering a hundred twenty-seven light-years pe
<hr></blockquote><!--EZCODE QUOTE END-->

Griff wanted to jump from Honogher to Mon Cal, which I estimated using my thumb and the official map was a rough distance of 12.5k lightyears. This is assuming that the SW galaxy is the same size as our IRL galaxy. Cruising at point five is stated in Dark Force Rising (a novel by one of the most respected SW authors) would be 127 LY/h. So from Honogher to Mon Cal it would take around 99 hours at point five past lightspeed. Remember though, your group travels at the speed of its slowest craft.

Posts usually take up 2 - (at most) 10 minutes of IC time.


With your group as spread out as it is, you will have to assume that any instant attacks will result in a surrender. You won't be able to spread your fleet out enough and have enough everywhere to withstand a pointed assault. You'll have to form a more reactive defense strategy than even-steven every planet gets six ISD's.
Posts: 2915
  • Posted On: Jun 3 2004 2:10am
A light-year is the distance travelled by light in one year. An Earth-based light-year is 9.461x1015m. However this is not appropriate in a STAR WARS context, because the galactic standard year is derived from the orbital period of Coruscant rather than Earth. As stated below in the time section, the standard year is slightly longer than the terrestrial equivalent. We assume that the standard second exactly equals the usual metric second. Therefore when a citizen of the Old Republic, Galactic Empire or New Republic quotes a distance in "light-years", the unit is actually 368/365.25 times our version of the light-year. (It is about 0.75% greater.) By the Coruscant definition, a light-year is approximately 9.531x1015m. In Shield of Lies, Lando Calrissian states that the galaxy is 120,000ly in diameter.


--------------------------------------------------------------------------------
m km ly pc
m 1 0.001 1.049x10-16 3.240x10-17/a
km 1000 1 1.049x10-13 3.240x10-14/a
ly 9.531x1015 9.531x1012 1 0.3088/a
pc 3.086x1016a 3.086x1013a 3.238a 1
--------------------------------------------------------------------------------

The value a=(Coruscant orbit semimajor axis)/(Earth orbit semimajor axis) is assumed to equal 1.
Posts: 2915
  • Posted On: Jun 3 2004 2:10am
The galactic standard second appears to be identical to the metric second. Higher units of time are reckoned according to the clock and calendar of Coruscant. A standard minute consists of 60 seconds; an hour consists of 60 minutes; a day consists of 24 hours. A standard week consists of 5 days; a month consists of seven weeks. A standard year is 368 days, including ten months, three fete weeks and three other holidays.